и обратная ей даны как: Ф𝑥𝑦𝑧 cos 𝛼 cos 𝛾 − cos 𝛽 sin 𝛼 sin 𝛾 = (cos 𝛽 cos 𝛾 sin 𝛼 + cos 𝛼 sin 𝛾 sin 𝛼 sin 𝛽 − cos 𝛾 sin 𝛼 − cos 𝛼 cos 𝛽 sin 𝛾 cos 𝛼 cos 𝛽 cos 𝛾 − sin 𝛼 sin 𝛾 cos 𝛼 sin 𝛽 cos 𝛼 cos 𝛾 − cos 𝛽 sin 𝛼 sin...
𝛾 ̃ Ф𝑥𝑦𝑧 = (− cos 𝛾 sin 𝛼 − cos 𝛼 cos 𝛽 sin 𝛾 sin 𝛽 sin 𝛾 где cos 𝛼 sin 𝛾 + cos 𝛽 cos 𝛾 sin 𝛼 cos 𝛼 cos 𝛽 cos 𝛾 − sin 𝛼 sin 𝛾 − cos 𝛾 sin 𝛽 sin 𝛽 sin 𝛾 − cos 𝛾 sin 𝛽 ), cos 𝛽 sin 𝛼 sin 𝛽 cos 𝛼 sin 𝛽 ), cos 𝛽 (4...

-Cauchy equation µ∇2u+ (λ+µ)∇(∇u) +ρΩ2u = 0 (2) where u(x,y) is the displacement field in the plate, λ,µ are the material dependent Lam´e coeffi- cients, andρis the density. Introducing elastic potentialsψ and A with the help of the Helmholtz decomposition...
is Poisson’s ratio [10]. E andσ are functions of the Lam´e coefficients [10]. Our conjecture is that both elastic potential are statistically independent Gaussian random waves (1). We write the potentials in the following form ψ(x) = 1ik l radicalbiggγ N...

. Direction of a narrow linear localization zone √ √ where ν = 1/κ2 − 4/3, 0 < κ < 3/2. By (4) the safety factor is m1 : m1 = 1 2τs 1 , κρga sin α (ν sin α − cos α) (6) here τs is the yield point. In paper [3] we obtained that deformation for a simple shear...
with dilatancy is localized in a narrow linear zone of thickness h inclined at an angle φ: φ = α − arcsin √ 1 ν2 +1 or 1 φ = α − arctg . ν (7) ν sin α − cos α √ . ν2 + 1 (8) In this case for the angle φ we compute sin φ = ν sin α − cos α √ , ν2 + 1 cos...

difference between the top inlet and the outlet equals ∆P = 5,149 Pа. At active mixing on the left inlet averageconsumption speed of a liquid was set con- stant and equal to 1 mm/s. Averageconsumption speed on the top inlet was set as follows: V=1mm/s+A×sin...
) b) Amount of sec- tions Pressure difference in the curved chan- nel, Pa Mixing in the curved channel, % Pressure difference in the direct chan- nel, Pa Mixing in the direct channel, % Mixing in the di- rect channel (ana- lytics ), Pа 1...

. For the extraordinary x-polarized waves we have a piecewise continuus solution. By using the transfer matrix approach the dispersion relation for the extraor- dinary waves is found as26,27 cos kBΛ = cos ked cos k0(Λ− d)− 1 2 ( ne no + no ne ) sin ked sin k0(Λ− d), where...
be written as ǫˆ = [ ǫe cos 2 φ+ ǫo sin 2 φ sin 2φ (ǫe − ǫo)/2 sin 2φ (ǫe − ǫo)/2 ǫe sin2 φ+ ǫo cos2 φ ] , (3) where the tilt angle φ is the polar angle in the x0y-plane. For brevity here and later on we omit the z-components the electromagnetic (EM) field...

ɯɨɡɹɢɧɨɦ ɞɚɧɧɨɝɨ ɜɢɪɭɫɚ. ȼ ɷɬɨɬ ɫɩɢɫɨɤ ɩɨɩɚɥɢ ɡɦɟɢ (Ji et al., 2020), ɹɳɟɪɵ (Lam et al., 2020) ɢ ɧɨɪɤɢ (Cheng et.al., 2020), ɨɞɧɚɤɨ ɩɪɨɦɟɠɭɬɨɱɧɵɯ ɯɨɡɹɟɜ ɦɨɠɟɬ ɛɵɬɶ ɢ ɧɟɫɤɨɥɶɤɨ. Ɍɚɤɢɦ ɨɛɪɚɡɨɦ, ɢɞɟɧɬɢɮɢɤɚɰɢɹ ɢɫɬɨɱɧɢɤɚ ɜɢɪɭɫɚ ɩɨɦɨɠɟɬ ɤɨɧɬɪɨɥɢɪɨɜɚɬɶ ɟɝɨ...
ɫɨɛɨɣ ɪɟɡɭɥɶɬɚɬ ɫɥɭɱɚɣɧɨɣ ɷɜɨɥɸɰɢɢ (Tang et al., 2020; Lam et al., 2020). ȼ ɰɟɥɨɦ, ɟɳɟ ɩɪɟɞɫɬɨɢɬ ɪɟɲɢɬɶ, ɩɨɧɚɞɨɛɢɥɫɹ ɥɢ SARS-CoV-2 ɩɪɨɦɟɠɭɬɨɱɧɵɣ ɯɨɡɹɢɧ, 20 ɩɪɟɠɞɟ ɱɟɦ ɨɧ ɫɦɨɝ ɡɚɪɚɡɢɬɶ ɥɸɞɟɣ, ɤɚɤ ɷɬɨ ɛɵɥɨ ɜ ɫɥɭɱɚɟ SARS-CoV ɢ ɞɪɭɝɢɯ HCoV. 1...

Проведены лабораторные исследования по переработке золотосодержащего концентрата месторождения «Джамгыр» с помощью реагента JIN CHAN (Цзинь Чань). Изучено влияние концентрации JIN CHAN, продолжительность выщелачивания, температура раствора. В...
Laboratory studies have been carried out on the processing of gold-bearing concentrate from the “Jamgyr” deposit using the JIN CHAN reagent. The influence of the concentration JIN CHAN, the duration of leaching, the temperature of the solution were...

-invariant symmetry in the solution for the ground state [11], 1 2 1 0 0 1 ( ) cos2 2 cos 2 , K i i i i K K U x x V x V x − + =− ⎡ ⎤ = − − β − π ⎢ ⎥⎣ ⎦ − π ∑ + − − = − = = = + = − + π π < < β = − + π π 0 1 0 1 1 0 1 0 ( 2 ), 0( 2 1); 2 2 sin 2 , 0 ; 2 sin 2 . i i i i...
.5]. In the interval [0.456, 0.5], a structure with two sublattices = 0.18138 (N is even), [xK] = K/2, is realized and, in the interval [0.43, 0.456], a sin- gle-dislocation structure with the sublattices = 0.19102, [xK] = K/2 – 1. Thus, for even K (N...

whether the presence of the radiation losses breaks that symmetry. Let us specify the propagation direction specified by arbitrarily azimuthal angle ϕ such that kx � k∥ cos�ϕ� and ky � k∥ sin�ϕ� with k∥ � ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi k2x...
into account that px → py and py → −px under rotation by ϕ � π, we can write W TE � h ffiffiffiffi γp p cos�ϕ�, ffiffiffiffiγpp sin�ϕ�, ffiffiffiffiγsp i , (5) W TM � h − ffiffiffiffi γp p sin�ϕ�, ffiffiffiffiγpp cos�ϕ�, 0 i : (6) Next, one can easily check...

, (4) where NS = ϕ/dϕ is the number of sublayers. Substitu- tion of Eqs. (2) and (3) gives: dJˆ = [ Ja Jb −J∗b J∗a ] , (5) where Ja = cos (dϕ) cos (dδ)− i sin (dδ), Jb = sin (dϕ) cos (dδ). Eigenvectors ~eJ of the matrix dJˆ describe polarization...
anisotropy angle defined as the following: cos (dυ) ≡ cos (dϕ) cos (dδ) . (7) The solution of Eq. (6) can then be written as g∓J = cos (dυ)∓ i sin (dυ) = exp (∓idυ) . The eigenvectors take the forms: ~eJ − = ~ete = [ cosϑ −i sinϑ ] , ~eJ + = ~eto = [ −i sinϑ...